Printable · GCSE Higher · ages 14-16
Algebra worksheet — GCSE Higher
Fifteen questions across the algebra statements at Higher tier. Choose the non-calculator filter to rehearse Paper 1, which counts for a third of the marks.
Non-calculator
Algebra worksheet — GCSE Higher
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- 1.A cyclist's speed-time graph is described as follows: speed increases steadily from 0 m/s to 8 m/s over the first 4 seconds, stays constant at 8 m/s for the next 6 seconds, then decreases steadily to 0 m/s over the final 2 seconds. Work out the total distance travelled.
- 2.A student is asked whether 3(x − 4) = 3x − 4 is an identity. Which statement gives the correct verdict and reason?
- 3.By completing the square, find the turning point of the curve y = x² + 6x + 2.y = x² + 6x + 2
- 4.For the graph of y = 1/x, where x cannot be zero, which of these statements is correct?
- 5.Work out the value of (x − 4)/2 + 3 when x = 10
- 6.Make x the subject of the formula y = 4(x − 6).
- 7.Solve the inequality 5 − x ≤ 2.
- 8.The height, h metres, of a ball t seconds after a stopwatch is started follows h = (t − 1)(5 − t) for 1 ≤ t ≤ 5, where h = 0 means the ball is at ground level. Work out the two times at which the ball is at ground level.
- 9.The graph of y = x² − 4x is translated by the vector (3, 0). Work out the equation of the image, giving your answer in the form y = x² + bx + c.y = x² − 4xy = x²
- 10.f(x) = x² − 1 and g(x) = 3x. Work out fg(4).y = x² − 1
- 11.A sequence has the position-to-term rule n² + 2, where n is the position number. Work out the 6th term.
- 12.The graph of y = f(x) has x-intercepts at x = −1 and x = 4. Which statement correctly describes the x-intercepts of y = f(2 − x)?
- 13.The nth term of a sequence is 2n² + 1. Work out the 4th term of the sequence.
- 14.ABCD is a parallelogram. A has coordinates (−3, 1), B has coordinates (2, 1) and C has coordinates (4, 4). Work out the coordinates of D.
- 15.The curve y = x² − 1 and the line y = 3x − 3 meet at two points. Work out the x-coordinates of those two points.y = 3x − 3y = x² − 1
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