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Worksheet: Ratio, proportion and rates of change
- 1.In a recipe the mass of chocolate to the mass of milk is in the ratio 1:4. Amelia uses 200 g of milk. Work out the mass of chocolate she needs.
- 2.A map has a scale of 1 : 25 000. Two towns are 5 km apart in real life. Work out the distance between the towns on the map, in centimetres.
- 3.The number of pupils who walk to school is 3 times the number who cycle. Write the ratio of the number who cycle to the number who walk, in its simplest form.
- 4.A straight-line graph shows the cost, C pounds, of hiring a small van for m miles driven. The line passes through the origin and the point (25, 20). Work out the gradient of the line.
- 5.A sum of £150 is divided between Ben and Chloe in the ratio 2:3. Work out Chloe's share.
- 6.1 litre = 100 centilitres. Work out how many centilitres there are in 6 litres.
- 7.A car uses 6 litres of petrol to travel 90 km. Write the ratio of the distance travelled in km to the amount of petrol used in litres, in its simplest form.
- 8.A plumber's charge, C pounds, for a job lasting h hours is shown on a straight-line graph. The line passes through the points (1, 45) and (3, 85). Work out what the gradient of this line represents, in context.
- 9.After a 20% discount, a jacket costs £48. Work out the original price of the jacket.
- 10.Paint costs £14.40 for every 20 m² of wall it covers. Assuming the same rate, work out the cost of the paint needed to cover 56 m² of wall.
- 11.3 pencils cost £1.20. Work out the cost of 7 pencils.
- 12.A cookery class lasts 45 minutes. A double lesson at school lasts 2 hours. Write the length of the cookery class as a fraction of the length of the double lesson. Give your answer in its simplest form.
- 13.Write 350 ml : 1.4 l as a ratio in its simplest form.
- 14.Write 75p : £1.50 as a ratio of whole numbers in its simplest form.
- 15.£5000 is invested in an account paying 4% compound interest each year. Work out the total interest earned after 3 years.
Answer key
- (d) 50 g — Method: the milk is 4 parts of the ratio, so use the milk to find the value of one part, then read off the chocolate, which is 1 part. Working: one part = 200 ÷ 4 = 50, and the chocolate is one part. Answer: 50 g. The distractors: 40 g comes from treating the 200 g as the total mass of the mixture and splitting it into 1 + 4 = 5 parts; 250 g is the total mass of the finished mixture, the 200 g of milk plus the chocolate, rather than the chocolate on its own; 800 g comes from multiplying 200 by 4 instead of dividing, which scales the milk up rather than down to the chocolate.
- (c) 20 cm — Convert 5 km to centimetres: 5 km = 5000 m = 500 000 cm. Divide by the scale factor: 500 000 ÷ 25 000 = 20, giving 20 cm. Converting only as far as metres, 5000 ÷ 25 000 = 0.2, gives 0.2 cm — the conversion to centimetres was never finished. Dropping a zero in the division gives 2 cm, ten times too small. Misreading the scale as 1 : 2500 instead of 1 : 25 000 gives 500 000 ÷ 2500 = 200 cm, ten times too big.
- (b) 1:3 — Let the number who cycle be 1 part. Since 3 times as many pupils walk, the number who walk is 3 parts. The ratio of cycle to walk is 1:3. (3:1 comes from writing the ratio the wrong way round, walk to cycle. 1:4 comes from treating “3 times as many” as “3 more”, so walk = cycle + 3, giving parts 1 and 4. 3:4 comes from comparing the number who walk with the total number of pupils, 3 parts out of 4 parts altogether, instead of comparing cycle with walk.)
- (a) 0.8 — The gradient of a line through the origin is the y-coordinate of a point divided by its x-coordinate: 20 ÷ 25 = 0.8. Choosing 1.25 comes from dividing the wrong way round, 25 ÷ 20. Choosing 20 comes from reading off the cost at the point instead of dividing it by the number of miles. Choosing 5 comes from subtracting the two coordinates (25 − 20) instead of dividing them.
- (c) £90 — Method: split the total amount into the number of parts shown by the ratio, then find Chloe's share. Working: the ratio 2:3 has 2 + 3 = 5 parts, so one part is £150 ÷ 5 = £30, and Chloe's share is 3 × £30 = £90. So Chloe receives £90. Distractor £60 is Ben's share, not Chloe's. Distractor £75 comes from splitting the money into two equal halves, ignoring the ratio. Distractor £30 is the value of one part, found correctly but never multiplied by 3.
- (c) 600 centilitres — Method: changing a larger unit into a smaller one means multiplying by the conversion factor given in the question. Working: 6 × 100 = 600. Answer: 600 centilitres. The distractors: 60 centilitres comes from multiplying by 10, as if a litre held 10 centilitres; 6000 centilitres comes from multiplying by 1000, which is the number of millilitres in a litre, not centilitres; 106 centilitres comes from adding 100 and 6 instead of multiplying.
- (a) 15:1 — Write the ratio distance : petrol using the numbers in the question: 90 : 6. Divide both parts by their highest common factor, 6, to give 15 : 1. (1:15 comes from writing the ratio the wrong way round, petrol : distance. 5:2 comes from dividing only the distance by 6 and leaving the 6 litres unchanged, giving 15:6, which does simplify to 5:2 — the error is the step before, because both parts of a ratio must be divided by the same number. 14:1 comes from subtracting at the first step instead of dividing, 90 − 6 = 84, and then writing 84 : 6 and dividing both parts by 6 to get 14 : 1; subtracting has no part in simplifying a ratio.)
- (a) The plumber charges £20 for each extra hour worked — The gradient is the change in C divided by the change in h: (85 − 45) ÷ (3 − 1) = 40 ÷ 2 = £20. On this graph the gradient represents the extra amount charged for each extra hour worked, so the answer is 'The plumber charges £20 for each extra hour worked'. Not dividing by the change in h gives 40, the option that reads 'charges £40 for each extra hour worked' — that is the total change in cost between the two points, not the rate per hour. Reading off the C-value of the first point, 45, gives the option using £45 — that is the cost of a job lasting 1 hour, not the rate. Treating the gradient as a flat total charge regardless of the time taken misunderstands what a straight-line graph through two different h-values shows: the cost does depend on h, so it cannot be a single fixed total.
- (b) £60 — £48 represents 100% − 20% = 80% of the original price. 1% = £48 ÷ 80 = £0.60, so 100% = £0.60 × 100 = £60.
- (a) £40.32 — Find the cost per square metre from the rate given: £14.40 ÷ 20 = £0.72 per m². Then multiply by the area to be covered: £0.72 × 56 = £40.32. Working out 14.40 × 20 ÷ 56 ≈ £5.14 uses the ratio the wrong way round, scaling down as if 56 m² needed less paint than 20 m². Stopping at £0.72 only gives the cost per square metre, not the cost for the whole wall. Working out 14.40 + (56 − 20) = £50.40 adds the extra square metres straight onto the cost in pounds, treating square metres and pounds as the same kind of quantity. Covering 56 m² costs £40.32.
- (a) £2.80 — Method: find the cost of one pencil first, then use it to find the cost of 7 pencils. Working: £1.20 ÷ 3 = £0.40 for one pencil, and £0.40 × 7 = £2.80. So 7 pencils cost £2.80. Distractor £8.40 comes from multiplying £1.20 by 7 without first dividing by 3 to find the cost of one pencil. Distractor £1.20 comes from assuming the price stays the same no matter how many pencils are bought. Distractor £0.40 is the cost of one pencil, found correctly but never multiplied by 7.
- (a) 3/8 — Convert 2 hours to minutes: 2 hours = 120 minutes. Form the fraction 45/120. Both numbers share a factor of 15, so 45 ÷ 15 = 3 and 120 ÷ 15 = 8, giving 3/8. 8/3 comes from writing the fraction the wrong way round, as 120/45. 9/40 comes from converting 2 hours using ×100 instead of ×60, treating it as 200 minutes, then simplifying 45/200. 45/2 comes from not converting the hours to minutes at all, and writing 45 over 2.
- (d) 1:4 — Convert 1.4 l to millilitres: 1.4 l = 1400 ml. The ratio is 350 : 1400. Divide both parts by 350: 350 ÷ 350 = 1 and 1400 ÷ 350 = 4, giving 1 : 4. Misreading 1.4 l as 14 (moving the decimal point) gives 350 : 14, which simplifies to 25 : 1 — a very different, implausible ratio. Dividing by 175 instead of 350 gives 2 : 8, which still shares a common factor of 2, so it is not fully simplified. Swapping the order gives 4 : 1, litres to millilitres the wrong way round.
- (c) 1:2 — Convert £1.50 into pence: £1.50 = 150p, so the ratio is 75 : 150. Dividing both parts by 75 gives 1 : 2. Getting 50 : 1 comes from not converting the units at all and simplifying 75 : 1.5. Getting 2 : 1 has the two parts the wrong way round. Getting 3 : 4 comes from reading 75p as 3/4 of a pound and then comparing it with £1 instead of £1.50.
- (c) £624.32 — A 4% rise is a multiplier of 1.04, applied once each year. After year 1: 5000 × 1.04 = 5200. After year 2: 5200 × 1.04 = 5408. After year 3: 5408 × 1.04 = 5624.32. The question asks for the interest, not the value of the account, so take away the amount invested at the start: 5624.32 − 5000 = 624.32. The total interest earned is £624.32.
GCSE Foundation — Ratio, proportion and rates of change
25% of a GCSE Foundation entry is ratio, proportion and rates of change, spread across all three papers rather than gathered into one. There are 15 ratio, proportion and rates of change statements to cover. Working through them one at a time beats mixed practice while a topic is still shaky — mixed practice tells you that something is wrong, not what. The ground it covers runs through converting between standard and compound units, scale factors, scale diagrams and maps, one quantity as a fraction of another, ratio notation and simplest form, dividing in a ratio and multiplicative relationships as ratios or fractions. Everything on this page is Foundation content, which means a Higher student needs it too — Higher is Foundation plus more, not instead of. With 50% AO1 and 50% across AO2 and AO3, fluency alone is not enough — the paper repeatedly asks what your answer means. Much of this is examined on Paper 1, where there is nothing to fall back on but written method.
- R1 — Converting between standard and compound units
- R2 — Scale factors, scale diagrams and maps
- R3 — One quantity as a fraction of another
- R4 — Ratio notation and simplest form
- R5 — Dividing in a ratio
- R6 — Multiplicative relationships as ratios or fractions
- R7 — Proportion as equality of ratios
- R8 — Ratios, fractions and linear functions
- R9 — Percentages and percentage change
- R10 — Direct and inverse proportion
- …and 5 more ratio, proportion and rates of change statements at this tier
Frequently asked questions
- How much of the GCSE Foundation paper is ratio, proportion and rates of change?
- 25% of the total marks, and the three papers each carry an equal share of the qualification, so it is spread across all of them rather than concentrated in one.
- How many topics are there in ratio, proportion and rates of change at GCSE Foundation?
- 15 DfE content statements, coded R1 to R16 within this area. Every question in the bank is tagged to one of them.
- Is any ratio, proportion and rates of change content on this page Higher only?
- No. Foundation pages only show statements a Foundation entry may be asked. The Higher-only ratio, proportion and rates of change material is on the GCSE Higher page for this area.
- Can I use a calculator for ratio, proportion and rates of change questions?
- Paper 1 is non-calculator; Papers 2 and 3 allow one. Of the 15 statements in this area, 6 are naturally non-calculator and 1 naturally calculator, with the rest workable either way — so practise both.
- What kind of marks does ratio, proportion and rates of change carry?
- The GCSE Foundation split is 50% AO1 (use and apply standard techniques), 25% AO2 (reason, interpret and communicate) and 25% AO3 (solve problems in and out of context). Questions in this area are set across all three.
- Are these past paper questions?
- No. Every question at /gcse-foundation is original, written to the DfE content statements and checked before it is published. We do not host past papers or mark schemes.
✍️ Written by the MathsUK teamChecked against the National Curriculum and GCSE specificationsLast updated: