Printable · GCSE Foundation · ages 14-16
Algebra worksheet — GCSE Foundation
Fifteen questions across the algebra statements at Foundation tier. Choose the non-calculator filter to rehearse Paper 1, which counts for a third of the marks.
Algebra worksheet — GCSE Foundation
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- 1.A straight line passes through the points (2, 7) and (5, 16). Work out the value of y when x = 0.
- 2.A plumber charges a £40 call-out fee plus £25 for each hour worked. The total charge, £C, for a job lasting h hours is given by C = 40 + 25h. Work out the charge for a job lasting 3 hours, and name what kind of statement C = 40 + 25h is.
- 3.A straight line has equation 4y = 12x + 20. Work out the gradient of the line.y = 12x + 20
- 4.The graph of y = x² − 7x + 2 crosses the x-axis at two points. One root, read from the graph, is approximately x = 0.30. Using the fact that the sum of the two roots of x² − 7x + 2 = 0 is 7, estimate the other root, correct to 2 decimal places.y = x² − 7x + 2
- 5.On a map, where each grid unit represents 1 km, Ravi's house is at (−3, 4) and the library is at (6, 4). Work out the distance between Ravi's house and the library.
- 6.Solve the inequality 6x ≥ 18.
- 7.Write down the y-intercept of the line with equation y = 3x + 8.y = 3x + 8
- 8.The point D has coordinates (3, −8). Write down the distance of D from the y-axis.
- 9.Make x the subject of the formula y = x/2 − 5.y = x
- 10.Solve the inequality 3x − 1 ≤ 11.
- 11.Two expressions are 6(x − 1) and 6x − 6. A student says these are equivalent for every value of x. Is the student correct?
- 12.To rearrange y = 2x − 5 to make x the subject, Sam writes: 'Add 5 to both sides to get y + 5 = 2x, then divide both sides by 2 to get x = (y + 5)/2.' Which statement about Sam's method is correct?y = 2x − 5
- 13.Priya buys b balloons for a party. Each balloon costs 15p. Write down an expression for the total cost, in pence.
- 14.Work out the values of x and y that satisfy both x + y = 10 and x − y = 4.
- 15.Work out the gradient of the straight line with equation y = (2x/5) − 3.
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