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Straight-line graphs and y = mx + c worksheet — GCSE Higher

Fifteen questions on "straight-line graphs and y = mx + c" — DfE statement A9. Print it, or print three versions so neighbours cannot copy by letter; the key gives the letter for each version.

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Straight-line graphs and y = mx + c worksheet — GCSE Higher

Maths · GCSE Higher · A9 · Straight-line graphs and y = mx + c · 15 questions

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1.A straight line has gradient −2 and passes through the point (3, 1). Work out the equation of the line.
(a)y = −2x + 7
(b)y = −2x − 5
(c)y = 2x + 7
(d)y = −2x + 1
2.Line L has equation y = 3x + 1. Which of these lines is perpendicular to L?
y = 3x + 1
(a)y = (1/3)x + 2
(b)y = −(1/3)x + 2
(c)y = −3x + 2
(d)y = 3x − 4
3.Line L has equation y = 2x + 3. Work out the equation of the line perpendicular to L that passes through the point (4, 1), giving your answer in the form x + 2y = c.
y = 2x + 3
(a)x + 2y = 9
(b)x − 2y = 2
(c)x + 2y = 6
(d)x + 2y = −2
4.A straight line has gradient −3 and passes through the point (0, 1). Work out the value of y when x = 2.
(a)7
(b)−5
(c)5
(d)−7
5.A garden path runs along the line 4x + y = 12. A drainage pipe must be laid perpendicular to the path, passing through the point (3, 1) where a sprinkler sits. Work out the equation of the pipe's line, giving your answer in the form y = mx + c.
(a)y = (1/4)x + 1/4
(b)y = −(1/4)x + 1/4
(c)y = (1/4)x − 1/4
(d)y = −4x + 13
6.A plumber charges a call-out fee plus an hourly rate. The total cost, y in pounds, of a job lasting x hours is given by y = 45x + 60. Work out the total cost of a job that lasts 3 hours.
y = 45x + 60
(a)£315
(b)£108
(c)£135
(d)£195
7.A straight line has gradient 3 and passes through the point (1, 4). Work out the equation of the line.
(a)y = x + 3
(b)y = 3x − 1
(c)y = 3x + 1
(d)y = 3x + 4
8.A student is asked whether the lines y = (2/5)x − 1 and 5y = −2x + 15 are perpendicular. The student answers: "Yes, because when I rearrange the second equation I get y = −(2/5)x + 3, and 2/5 times −2/5 is negative." Which of these is a correct comment on the student's reasoning?
y = -2x + 15
(a)Wrong — the rearrangement is incorrect.
(b)Right — 2/5 and −2/5 are negatives of each other.
(c)Wrong — the product is −4/25, not −1.
(d)Right — a negative product always means perpendicular.
9.A straight line passes through the points (2, 5) and (4, 11). Work out the gradient of the line.
(a)8/3
(b)−3
(c)3
(d)1/3
10.A straight line passes through the points (−1, 2) and (3, 14). Work out the equation of the line.
(a)y = 6x − 4
(b)y = x/3 + 13
(c)y = 3x + 5
(d)y = 3x + 23
11.Work out the equation of the straight line that passes through (−2, 3) and (4, −9).
(a)y = −2x − 1
(b)y = −2x + 1
(c)y = −(1/2)x + 2
(d)y = 2x + 7
12.A straight line passes through the points (1, 3) and (2, 5). Work out the equation of the line.
(a)y = x + 2
(b)y = 2x − 1
(c)y = 2x + 1
(d)y = 2x + 3
13.Line P has equation y = −2x + 5 and line Q has equation 2y = x + 6. Are lines P and Q perpendicular to each other?
y = -2x + 5y = x + 6
(a)Yes — the gradients multiply to −2 × 1/2 = −1.
(b)No — the product is −1, but perpendicular needs 1.
(c)No — Q's gradient is 2, and −2 × 2 = −4, not −1.
(d)Yes — both equations have a negative x-term.
14.Which of these pairs of lines are perpendicular to each other?
(a)y = 2x and y = 2x + 1
(b)y = 2x and y = −(1/2)x + 1
(c)y = 2x and y = −2x + 1
(d)y = 2x and y = (1/2)x + 1
15.Work out the equation of the straight line through the points (−3, 4) and (1, −8).
(a)y = −3x − 5
(b)y = 3x − 11
(c)y = −3x + 5
(d)y = −3x + 11

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