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Straight-line graphs and y = mx + c worksheet — GCSE Higher

Fifteen questions on "straight-line graphs and y = mx + c" — DfE statement A9. Print it, or print three versions so neighbours cannot copy by letter; the key gives the letter for each version.

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Straight-line graphs and y = mx + c worksheet — GCSE Higher

Maths · GCSE Higher · A9 · Straight-line graphs and y = mx + c · 15 questions

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1.A straight line passes through the points (−1, 2) and (3, 14). Work out the equation of the line.
(a)y = 6x − 4
(b)y = x/3 + 13
(c)y = 3x + 5
(d)y = 3x + 23
2.Line L has equation y = 2x + 3. Work out the equation of the line perpendicular to L that passes through the point (4, 1), giving your answer in the form x + 2y = c.
y = 2x + 3
(a)x + 2y = 9
(b)x − 2y = 2
(c)x + 2y = 6
(d)x + 2y = −2
3.A straight line has gradient −3 and passes through the point (0, 1). Work out the value of y when x = 2.
(a)7
(b)−5
(c)5
(d)−7
4.Work out the equation of the straight line through the points (−2, 1) and (0, 7).
(a)y = −3x + 7
(b)y = 3x + 1
(c)y = 3x + 7
(d)y = (1/3)x + 7
5.A plumber charges a call-out fee plus an hourly rate. The total cost, y in pounds, of a job lasting x hours is given by y = 45x + 60. Work out the total cost of a job that lasts 3 hours.
y = 45x + 60
(a)£315
(b)£108
(c)£135
(d)£195
6.A line has equation y = −4x + 1. Work out the equation of the line perpendicular to it that passes through the point (0, 3).
y = -4x + 1
(a)y = −4x + 3
(b)y = (−1/4)x + 3
(c)y = 4x + 3
(d)y = (1/4)x + 3
7.A cycle route is 84 km long. Freya sets off along it at a steady 14 km/h. Write down the function for the distance y, in kilometres, that is still to be cycled after x hours.
(a)y = 84 + 14x
(b)y = 84 − 14x
(c)y = 14 − 84x
(d)y = 14x − 84
8.Line L has equation y = 3x + 1. Which of these lines is perpendicular to L?
y = 3x + 1
(a)y = (1/3)x + 2
(b)y = −(1/3)x + 2
(c)y = −3x + 2
(d)y = 3x − 4
9.Line L has equation y = 3x − 2. Work out the gradient of a line perpendicular to L.
y = 3x − 2
(a)−1/3
(b)1/3
(c)3
(d)−3
10.A straight line has gradient −2 and passes through the point (3, 1). Work out the equation of the line.
(a)y = −2x + 7
(b)y = −2x − 5
(c)y = 2x + 7
(d)y = −2x + 1
11.Work out the equation of the straight line through the points (−3, 4) and (1, −8).
(a)y = −3x − 5
(b)y = 3x − 11
(c)y = −3x + 5
(d)y = −3x + 11
12.Line P has equation y = −2x + 5 and line Q has equation 2y = x + 6. Are lines P and Q perpendicular to each other?
y = -2x + 5y = x + 6
(a)Yes — the gradients multiply to −2 × 1/2 = −1.
(b)No — the product is −1, but perpendicular needs 1.
(c)No — Q's gradient is 2, and −2 × 2 = −4, not −1.
(d)Yes — both equations have a negative x-term.
13.A straight line passes through the points (2, 5) and (4, 11). Work out the gradient of the line.
(a)8/3
(b)−3
(c)3
(d)1/3
14.A straight line has gradient 3 and passes through the point (1, 4). Work out the equation of the line.
(a)y = x + 3
(b)y = 3x − 1
(c)y = 3x + 1
(d)y = 3x + 4
15.A student is asked whether the lines y = (2/5)x − 1 and 5y = −2x + 15 are perpendicular. The student answers: "Yes, because when I rearrange the second equation I get y = −(2/5)x + 3, and 2/5 times −2/5 is negative." Which of these is a correct comment on the student's reasoning?
y = -2x + 15
(a)Wrong — the rearrangement is incorrect.
(b)Right — 2/5 and −2/5 are negatives of each other.
(c)Wrong — the product is −4/25, not −1.
(d)Right — a negative product always means perpendicular.

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